Which of the following will be more soluble in an acidic solution than in pure water? CaSo4, BaSO3, CuBr, Sn(OH)2, RbClO4

Question

Question:

Which of the following will be more soluble in an acidic solution than in pure water? CaSo4, BaSO3, CuBr, Sn(OH)2, RbClO4

How do we check whether the salt is acidic or basic?

Answer:

To check whether a salt is acidic or basic, check the conjugates of the cation and anion of the salt. If one conjugate is a strong acid, the salt is acidic. If one conjugate is a strong base, the salt is basic. If both conjugates are strong, the salt is neutral. If both conjugates are weak, compare the dissociation constants of the two conjugates.

Answer & Explanation:

The salt that will be more soluble in acidic solution is a basic salt.

1. Calcium sulfate is a basic salt because sulfate is a weak base. It is slightly soluble in water.

2. Barium sulfite is a basic salt as well. It is slightly soluble in water.

3. Copper bromide is a neutral salt that is slightly soluble in water.

4. Tin(II) hydroxide is a basic salt because it has hydroxide ions.

5. Rubidium perchlorate is a neutral salt.

Since Tin(II) hydroxide is the strongest basic salt, it is the most soluble in acid.

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Sam Professor 2 years 1 Answer 1692 views 0

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