## What is the strength of the electric field at the position indicated by the dot in Figure 1?

Question Part A) What is the strength of the electric field at the position indicated by the dot in (Figure 1)?

E = _____ N/C

Part B) What is the direction of the electric field at the position indicated by the dot in the figure? Specify the direction as an angle above the horizontal line.

θ = _____

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2 years 1 Answer 6150 views 0

1. Superposition Principle of Electric Field:
Like the electric field at a point in space because of a solitary charge, electric field at a point in space because of the arrangement of charges is characterized to be the power experienced by a unit test charge put by then, without exasperating the first places of charges. We can utilize Coulomb’s law and the
superposition guideline to decide this field anytime.
The separation of position (demonstrated by the spot) from the two-point charges is same: r=5√2 cm
Likewise, the charges of two-point charges is same: q=+1.0 nC
In this way, the quality of electric field of the two-point charges is additionally same at the position shown by spot:
E=kq/r2
=9×109×1.0×10−9/ (5(√2) ×10−2)2
=1.80×103N/C
By balance the electric fields by two-point charges makes an edge of 45∘45∘ with level, one in upward heading and the other descending way.
Along these lines, their vertical segment will offset and even segment will include.
Section A) Thus the quality of the electric field at the position demonstrated by the speck in Figure is:
Enet=2Ecos45∘
=2× (1.80×103) × (1/√2)
=2.55×103N/C
Part B) The bearing of the electric field at the position demonstrated by the spot in the figure is along the level line as vertical segments of electric field counteract one another.
In this way, θ=0.00∘