What is the average of the integers from 25 to 41?

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  1. To do this, normally you could do the repetitive work of contributing every one of the numbers from 25–41 and partitioning that aggregate by 16. Or then again you can simply take the contrast between the greatest and least of the range for this situation 41–25=16. At that point isolate that distinction by 2 and if the remainder is an entire number subtract that number from the most extreme in the range. So 16/2=8 and 41–8=33. It seems like a long and complex procedure, however when you put it in straightforward terms, you’re simply finding the center number for the distinction between the most extreme and least of the given range. As an additional note, in the event that the remainder is certifiably not an entire, at that point round it up. Thus, for numbers 0–5; the procedure would be 5–0=5 5/2= 2.5, and 2.5 gathered together is 3. This can be scientifically checked by including 1+2+3+4+5=15 and 15/5 since there are 5 things or things in the given range, we isolate 15/5=3.

    At last, the solution to your concern is 33

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