Balance the following equation in acidic conditions. Phases are optional. Cr^2+ + H_2 MoO_4

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  1. Cr^2+ + H_2 MoO_4 – > Cr^3+ + Mo
    Redox Reaction:
    Redox response is a sort of response wherein oxidation and decrease happen at the same time.
    The redox response can be separated into two sections oxidation half and decrease half.
    Answer and Explanation:
    The following is the given response:
    Cr2++H2MoO4→Cr3++Mo
    Oxidation half-response
    Cr2+→Cr3+
    • Balancing Charge:
    Cr2+→Cr3++e−
    Presently,
    Decrease half-response
    MoO2−4→Mo
    Adjusting the decrease half-response we get,
    MoO2−4+8H++6e−→Mo+4H2O
    Presently,
    Including both the conditions so that the electrons get counterbalanced.
    6Cr2++H2MoO4+6H+→6Cr3++Mo+4H2O

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